Base | Representation |
---|---|
bin | 1011111100011010100011… |
… | …0000001000010110110111 |
3 | 1201111110101201120210220201 |
4 | 2333012220300020112313 |
5 | 3210130423312311203 |
6 | 43533001453541331 |
7 | 2523536511001216 |
oct | 277065060102667 |
9 | 51443351523821 |
10 | 13132546213303 |
11 | 4203532a77640 |
12 | 15812131a4847 |
13 | 74351722002a |
14 | 33589373107d |
15 | 17b91ad03e1d |
hex | bf1a8c085b7 |
13132546213303 has 4 divisors (see below), whose sum is σ = 14326414050888. Its totient is φ = 11938678375720.
The previous prime is 13132546213291. The next prime is 13132546213337. The reversal of 13132546213303 is 30331264523131.
It is a happy number.
13132546213303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13132546213303 - 217 = 13132546082231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13132546213363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596933918776 + ... + 596933918797.
It is an arithmetic number, because the mean of its divisors is an integer number (3581603512722).
Almost surely, 213132546213303 is an apocalyptic number.
13132546213303 is a deficient number, since it is larger than the sum of its proper divisors (1193867837585).
13132546213303 is a wasteful number, since it uses less digits than its factorization.
13132546213303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1193867837584.
The product of its (nonzero) digits is 116640, while the sum is 37.
The spelling of 13132546213303 in words is "thirteen trillion, one hundred thirty-two billion, five hundred forty-six million, two hundred thirteen thousand, three hundred three".
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