Base | Representation |
---|---|
bin | 11000011101100100… |
… | …11011000110100001 |
3 | 1020220021001120200221 |
4 | 30032302123012201 |
5 | 203344022013441 |
6 | 10011101443041 |
7 | 643306445002 |
oct | 141662330641 |
9 | 36807046627 |
10 | 13133001121 |
11 | 562a267139 |
12 | 2666270481 |
13 | 1313acb4a6 |
14 | 8c82ab1a9 |
15 | 51ce748d1 |
hex | 30ec9b1a1 |
13133001121 has 2 divisors, whose sum is σ = 13133001122. Its totient is φ = 13133001120.
The previous prime is 13133001061. The next prime is 13133001157. The reversal of 13133001121 is 12110033131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8082909025 + 5050092096 = 89905^2 + 71064^2 .
It is a cyclic number.
It is not a de Polignac number, because 13133001121 - 215 = 13132968353 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13133001095 and 13133001104.
It is not a weakly prime, because it can be changed into another prime (13133002121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566500560 + 6566500561.
It is an arithmetic number, because the mean of its divisors is an integer number (6566500561).
Almost surely, 213133001121 is an apocalyptic number.
It is an amenable number.
13133001121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133001121 is an equidigital number, since it uses as much as digits as its factorization.
13133001121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 13133001121 its reverse (12110033131), we get a palindrome (25243034252).
The spelling of 13133001121 in words is "thirteen billion, one hundred thirty-three million, one thousand, one hundred twenty-one".
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