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13133005147 is a prime number
BaseRepresentation
bin11000011101100100…
…11100000101011011
31020220021001210020001
430032302130011123
5203344022131042
610011101513431
7643306462513
oct141662340533
936807053201
1013133005147
11562a26a169
122666272877
131313b00282
148c82ac843
1551ce75bb7
hex30ec9c15b

13133005147 has 2 divisors, whose sum is σ = 13133005148. Its totient is φ = 13133005146.

The previous prime is 13133005079. The next prime is 13133005153. The reversal of 13133005147 is 74150033131.

13133005147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13133005147 is a prime.

It is a super-2 number, since 2×131330051472 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13133005247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566502573 + 6566502574.

It is an arithmetic number, because the mean of its divisors is an integer number (6566502574).

Almost surely, 213133005147 is an apocalyptic number.

13133005147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133005147 is an equidigital number, since it uses as much as digits as its factorization.

13133005147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780, while the sum is 28.

Adding to 13133005147 its reverse (74150033131), we get a palindrome (87283038278).

The spelling of 13133005147 in words is "thirteen billion, one hundred thirty-three million, five thousand, one hundred forty-seven".