Base | Representation |
---|---|
bin | 1011111100011100010011… |
… | …1111011111011011011101 |
3 | 1201111111121202002202211201 |
4 | 2333013010333133123131 |
5 | 3210132411110031023 |
6 | 43533120500515501 |
7 | 2523554323066342 |
oct | 277070477373335 |
9 | 51444552082751 |
10 | 13133020002013 |
11 | 420375646105a |
12 | 15813259abb91 |
13 | 743591428792 |
14 | 3358da6227c9 |
15 | 17b9476e0bad |
hex | bf1c4fdf6dd |
13133020002013 has 4 divisors (see below), whose sum is σ = 13199015077600. Its totient is φ = 13067024926428.
The previous prime is 13133020001999. The next prime is 13133020002029. The reversal of 13133020002013 is 31020002033131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13133020002013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13133020002073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32997537495 + ... + 32997537892.
It is an arithmetic number, because the mean of its divisors is an integer number (3299753769400).
Almost surely, 213133020002013 is an apocalyptic number.
It is an amenable number.
13133020002013 is a deficient number, since it is larger than the sum of its proper divisors (65995075587).
13133020002013 is an equidigital number, since it uses as much as digits as its factorization.
13133020002013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65995075586.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13133020002013 its reverse (31020002033131), we get a palindrome (44153022035144).
The spelling of 13133020002013 in words is "thirteen trillion, one hundred thirty-three billion, twenty million, two thousand, thirteen".
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