Base | Representation |
---|---|
bin | 1011111100011100010110… |
… | …1010101000111101110011 |
3 | 1201111111122112101102222001 |
4 | 2333013011222220331303 |
5 | 3210132422004011032 |
6 | 43533121543154431 |
7 | 2523554521166635 |
oct | 277070552507563 |
9 | 51444575342861 |
10 | 13133031313267 |
11 | 42037618873a8 |
12 | 1581329745a17 |
13 | 743593889128 |
14 | 3358dbd28a55 |
15 | 17b9486c73e7 |
hex | bf1c5aa8f73 |
13133031313267 has 2 divisors, whose sum is σ = 13133031313268. Its totient is φ = 13133031313266.
The previous prime is 13133031313261. The next prime is 13133031313271. The reversal of 13133031313267 is 76231313033131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13133031313267 is a prime.
It is a super-2 number, since 2×131330313132672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13133031313261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566515656633 + 6566515656634.
It is an arithmetic number, because the mean of its divisors is an integer number (6566515656634).
Almost surely, 213133031313267 is an apocalyptic number.
13133031313267 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133031313267 is an equidigital number, since it uses as much as digits as its factorization.
13133031313267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 37.
Adding to 13133031313267 its reverse (76231313033131), we get a palindrome (89364344346398).
The spelling of 13133031313267 in words is "thirteen trillion, one hundred thirty-three billion, thirty-one million, three hundred thirteen thousand, two hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •