Base | Representation |
---|---|
bin | 10011000111000111011… |
… | …000110101100101011001 |
3 | 11122112212211211210010001 |
4 | 103013013120311211121 |
5 | 133004124402432301 |
6 | 2443154255253001 |
7 | 163612023346534 |
oct | 23070730654531 |
9 | 4575784753101 |
10 | 1313310202201 |
11 | 466a7640a0a8 |
12 | 192640b1a161 |
13 | 96ac982982a |
14 | 477c91c1a1b |
15 | 242676edc01 |
hex | 131c7635959 |
1313310202201 has 2 divisors, whose sum is σ = 1313310202202. Its totient is φ = 1313310202200.
The previous prime is 1313310202187. The next prime is 1313310202241. The reversal of 1313310202201 is 1022020133131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1313199110601 + 111091600 = 1145949^2 + 10540^2 .
It is an emirp because it is prime and its reverse (1022020133131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313310202201 - 27 = 1313310202073 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313310202241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656655101100 + 656655101101.
It is an arithmetic number, because the mean of its divisors is an integer number (656655101101).
Almost surely, 21313310202201 is an apocalyptic number.
It is an amenable number.
1313310202201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313310202201 is an equidigital number, since it uses as much as digits as its factorization.
1313310202201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1313310202201 its reverse (1022020133131), we get a palindrome (2335330335332).
The spelling of 1313310202201 in words is "one trillion, three hundred thirteen billion, three hundred ten million, two hundred two thousand, two hundred one".
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