Base | Representation |
---|---|
bin | 111101001001111111… |
… | …1110100100101110010 |
3 | 110112222202022212021101 |
4 | 1322103333310211302 |
5 | 4122431443000424 |
6 | 140155540315014 |
7 | 12326346403420 |
oct | 1722377644562 |
9 | 415882285241 |
10 | 131332000114 |
11 | 50774543577 |
12 | 215529a2a6a |
13 | c4ccb34c93 |
14 | 64dc35a110 |
15 | 3639c75344 |
hex | 1e93ff4972 |
131332000114 has 16 divisors (see below), whose sum is σ = 225179925696. Its totient is φ = 56275304400.
The previous prime is 131332000069. The next prime is 131332000117. The reversal of 131332000114 is 411000233131.
It is a junction number, because it is equal to n+sod(n) for n = 131332000091 and 131332000100.
It is not an unprimeable number, because it can be changed into a prime (131332000117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 736632 + ... + 897379.
It is an arithmetic number, because the mean of its divisors is an integer number (14073745356).
Almost surely, 2131332000114 is an apocalyptic number.
131332000114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
131332000114 is a deficient number, since it is larger than the sum of its proper divisors (93847925582).
131332000114 is a wasteful number, since it uses less digits than its factorization.
131332000114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1639761.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 131332000114 its reverse (411000233131), we get a palindrome (542332233245).
The spelling of 131332000114 in words is "one hundred thirty-one billion, three hundred thirty-two million, one hundred fourteen", and thus it is an aban number.
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