Base | Representation |
---|---|
bin | 1011111101100011000… |
… | …01011101110010101011 |
3 | 1110021212022110010000201 |
4 | 11332301201131302223 |
5 | 23213212024430011 |
6 | 512451053213031 |
7 | 41456653224355 |
oct | 5766141356253 |
9 | 1407768403021 |
10 | 411000233131 |
11 | 149338a0a364 |
12 | 677a3191177 |
13 | 2c9ac617b27 |
14 | 15c6d0d40d5 |
15 | aa574d1cc1 |
hex | 5fb185dcab |
411000233131 has 2 divisors, whose sum is σ = 411000233132. Its totient is φ = 411000233130.
The previous prime is 411000233107. The next prime is 411000233153. The reversal of 411000233131 is 131332000114.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-411000233131 is a prime.
It is a super-2 number, since 2×4110002331312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 411000233099 and 411000233108.
It is not a weakly prime, because it can be changed into another prime (411000233101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205500116565 + 205500116566.
It is an arithmetic number, because the mean of its divisors is an integer number (205500116566).
Almost surely, 2411000233131 is an apocalyptic number.
411000233131 is a deficient number, since it is larger than the sum of its proper divisors (1).
411000233131 is an equidigital number, since it uses as much as digits as its factorization.
411000233131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 411000233131 its reverse (131332000114), we get a palindrome (542332233245).
The spelling of 411000233131 in words is "four hundred eleven billion, two hundred thirty-three thousand, one hundred thirty-one".
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