Search a number
-
+
131332400417 is a prime number
BaseRepresentation
bin111101001010000000…
…1010110010100100001
3110112222210002012101102
41322110001112110201
54122432043303132
6140155553044145
712326352661451
oct1722401262441
9415883065342
10131332400417
11507747972a9
1221552b56655
13c4ccc4524a
1464dc421d61
153639d03c62
hex1e94056521

131332400417 has 2 divisors, whose sum is σ = 131332400418. Its totient is φ = 131332400416.

The previous prime is 131332400399. The next prime is 131332400429. The reversal of 131332400417 is 714004233131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126729592081 + 4602808336 = 355991^2 + 67844^2 .

It is a cyclic number.

It is not a de Polignac number, because 131332400417 - 214 = 131332384033 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131332400417.

It is not a weakly prime, because it can be changed into another prime (131332400477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666200208 + 65666200209.

It is an arithmetic number, because the mean of its divisors is an integer number (65666200209).

Almost surely, 2131332400417 is an apocalyptic number.

It is an amenable number.

131332400417 is a deficient number, since it is larger than the sum of its proper divisors (1).

131332400417 is an equidigital number, since it uses as much as digits as its factorization.

131332400417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 131332400417 its reverse (714004233131), we get a palindrome (845336633548).

The spelling of 131332400417 in words is "one hundred thirty-one billion, three hundred thirty-two million, four hundred thousand, four hundred seventeen".