Base | Representation |
---|---|
bin | 111101001010000000… |
… | …1010110010100100001 |
3 | 110112222210002012101102 |
4 | 1322110001112110201 |
5 | 4122432043303132 |
6 | 140155553044145 |
7 | 12326352661451 |
oct | 1722401262441 |
9 | 415883065342 |
10 | 131332400417 |
11 | 507747972a9 |
12 | 21552b56655 |
13 | c4ccc4524a |
14 | 64dc421d61 |
15 | 3639d03c62 |
hex | 1e94056521 |
131332400417 has 2 divisors, whose sum is σ = 131332400418. Its totient is φ = 131332400416.
The previous prime is 131332400399. The next prime is 131332400429. The reversal of 131332400417 is 714004233131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126729592081 + 4602808336 = 355991^2 + 67844^2 .
It is a cyclic number.
It is not a de Polignac number, because 131332400417 - 214 = 131332384033 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131332400417.
It is not a weakly prime, because it can be changed into another prime (131332400477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666200208 + 65666200209.
It is an arithmetic number, because the mean of its divisors is an integer number (65666200209).
Almost surely, 2131332400417 is an apocalyptic number.
It is an amenable number.
131332400417 is a deficient number, since it is larger than the sum of its proper divisors (1).
131332400417 is an equidigital number, since it uses as much as digits as its factorization.
131332400417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 131332400417 its reverse (714004233131), we get a palindrome (845336633548).
The spelling of 131332400417 in words is "one hundred thirty-one billion, three hundred thirty-two million, four hundred thousand, four hundred seventeen".
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