Base | Representation |
---|---|
bin | 11101110111001000110101… |
… | …110011000001000001000101 |
3 | 122020000020220122021112021012 |
4 | 131313020311303001001011 |
5 | 114203222240102334140 |
6 | 1143153135530532005 |
7 | 36443311420356200 |
oct | 3567106563010105 |
9 | 566006818245235 |
10 | 131332412543045 |
11 | 3893484406277a |
12 | 12891127297005 |
13 | 583879380257c |
14 | 2460746358937 |
15 | 102b3cdcea265 |
hex | 777235cc1045 |
131332412543045 has 48 divisors (see below), whose sum is σ = 183535323811200. Its totient is φ = 89955377285760.
The previous prime is 131332412543023. The next prime is 131332412543141. The reversal of 131332412543045 is 540345214233131.
It is not a de Polignac number, because 131332412543045 - 28 = 131332412542789 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131332412542993 and 131332412543011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 786663230 + ... + 786830160.
It is an arithmetic number, because the mean of its divisors is an integer number (3823652579400).
Almost surely, 2131332412543045 is an apocalyptic number.
It is an amenable number.
131332412543045 is a deficient number, since it is larger than the sum of its proper divisors (52202911268155).
131332412543045 is a wasteful number, since it uses less digits than its factorization.
131332412543045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170538 (or 170531 counting only the distinct ones).
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 131332412543045 its reverse (540345214233131), we get a palindrome (671677626776176).
The spelling of 131332412543045 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, four hundred twelve million, five hundred forty-three thousand, forty-five".
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