Base | Representation |
---|---|
bin | 11101110111001000111100… |
… | …011001101011000111111011 |
3 | 122020000021012100202121111121 |
4 | 131313020330121223013323 |
5 | 114203223001433342113 |
6 | 1143153154525410111 |
7 | 36443314234211206 |
oct | 3567107431530773 |
9 | 566007170677447 |
10 | 131332523340283 |
11 | 389348a0659341 |
12 | 12891158409937 |
13 | 58387b0756775 |
14 | 2460756d5a93d |
15 | 102b3d88d3e8d |
hex | 77723c66b1fb |
131332523340283 has 2 divisors, whose sum is σ = 131332523340284. Its totient is φ = 131332523340282.
The previous prime is 131332523340257. The next prime is 131332523340331. The reversal of 131332523340283 is 382043325233131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131332523340283 is a prime.
It is a super-3 number, since 3×1313325233402833 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131332523340383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666261670141 + 65666261670142.
It is an arithmetic number, because the mean of its divisors is an integer number (65666261670142).
Almost surely, 2131332523340283 is an apocalyptic number.
131332523340283 is a deficient number, since it is larger than the sum of its proper divisors (1).
131332523340283 is an equidigital number, since it uses as much as digits as its factorization.
131332523340283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 43.
The spelling of 131332523340283 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, five hundred twenty-three million, three hundred forty thousand, two hundred eighty-three".
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