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13133304022 = 26566652011
BaseRepresentation
bin11000011101100111…
…00101000011010110
31020220021121222012111
430032303211003112
5203344111212042
610011112141234
7643312146046
oct141663450326
936807558174
1013133304022
11562a453773
12266639781a
131313ba6317
148c8349726
1551ced4517
hex30ece50d6

13133304022 has 4 divisors (see below), whose sum is σ = 19699956036. Its totient is φ = 6566652010.

The previous prime is 13133303983. The next prime is 13133304091. The reversal of 13133304022 is 22040333131.

13133304022 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13133303984 and 13133304002.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283326004 + ... + 3283326007.

It is an arithmetic number, because the mean of its divisors is an integer number (4924989009).

Almost surely, 213133304022 is an apocalyptic number.

13133304022 is a deficient number, since it is larger than the sum of its proper divisors (6566652014).

13133304022 is an equidigital number, since it uses as much as digits as its factorization.

13133304022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6566652013.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 13133304022 its reverse (22040333131), we get a palindrome (35173637153).

The spelling of 13133304022 in words is "thirteen billion, one hundred thirty-three million, three hundred four thousand, twenty-two".

Divisors: 1 2 6566652011 13133304022