Base | Representation |
---|---|
bin | 10011000111001000101… |
… | …000010010110010101011 |
3 | 11122112221022001000010212 |
4 | 103013020220102302223 |
5 | 133004200220444321 |
6 | 2443200321531335 |
7 | 163612365400523 |
oct | 23071050226253 |
9 | 4575838030125 |
10 | 1313331031211 |
11 | 466a87146261 |
12 | 192647aa3b4b |
13 | 96b00c403a4 |
14 | 477cbc84683 |
15 | 2426946555b |
hex | 131c8a12cab |
1313331031211 has 2 divisors, whose sum is σ = 1313331031212. Its totient is φ = 1313331031210.
The previous prime is 1313331031183. The next prime is 1313331031219. The reversal of 1313331031211 is 1121301333131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313331031211 is a prime.
It is a super-2 number, since 2×13133310312112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1313331031219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656665515605 + 656665515606.
It is an arithmetic number, because the mean of its divisors is an integer number (656665515606).
Almost surely, 21313331031211 is an apocalyptic number.
1313331031211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313331031211 is an equidigital number, since it uses as much as digits as its factorization.
1313331031211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 1313331031211 its reverse (1121301333131), we get a palindrome (2434632364342).
The spelling of 1313331031211 in words is "one trillion, three hundred thirteen billion, three hundred thirty-one million, thirty-one thousand, two hundred eleven".
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