Base | Representation |
---|---|
bin | 1011111100011101100110… |
… | …1001001011011011100111 |
3 | 1201111112111220001101200222 |
4 | 2333013121221023123213 |
5 | 3210134113304140341 |
6 | 43533215114554555 |
7 | 2523566031052205 |
oct | 277073151133347 |
9 | 51445456041628 |
10 | 13133366474471 |
11 | 4203913a96a31 |
12 | 1581401a38a5b |
13 | 743618148179 |
14 | 335930652075 |
15 | 17b967d2e44b |
hex | bf1d9a4b6e7 |
13133366474471 has 4 divisors (see below), whose sum is σ = 13185690643944. Its totient is φ = 13081042305000.
The previous prime is 13133366474441. The next prime is 13133366474483. The reversal of 13133366474471 is 17447466333131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13133366474471 - 218 = 13133366212327 is a prime.
It is a super-3 number, since 3×131333664744713 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13133366474441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26162084360 + ... + 26162084861.
It is an arithmetic number, because the mean of its divisors is an integer number (3296422660986).
Almost surely, 213133366474471 is an apocalyptic number.
13133366474471 is a deficient number, since it is larger than the sum of its proper divisors (52324169473).
13133366474471 is an equidigital number, since it uses as much as digits as its factorization.
13133366474471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52324169472.
The product of its digits is 9144576, while the sum is 53.
The spelling of 13133366474471 in words is "thirteen trillion, one hundred thirty-three billion, three hundred sixty-six million, four hundred seventy-four thousand, four hundred seventy-one".
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