131334101433132 has 96 divisors (see below), whose sum is σ = 333069048903360. Its totient is φ = 40037070044160.

The previous prime is 131334101433053. The next prime is 131334101433167. The reversal of 131334101433132 is 231334101433131.

It is a junction number, because it is equal to n+sod(n) for n = 131334101433093 and 131334101433102.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 261151282 + ... + 261653702.

It is an arithmetic number, because the mean of its divisors is an integer number (3469469259410).

Almost surely, 2^{131334101433132} is an apocalyptic number.

131334101433132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131334101433132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (166534524451680).

131334101433132 is an abundant number, since it is smaller than the sum of its proper divisors (201734947470228).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131334101433132 is a wasteful number, since it uses less digits than its factorization.

131334101433132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 517923 (or 517921 counting only the distinct ones).

The product of its (nonzero) digits is 23328, while the sum is 33.

Adding to 131334101433132 its reverse (231334101433131), we get a palindrome (362668202866263).

Subtracting 131334101433132 from its reverse (231334101433131), we obtain a palindrome (99999999999999).

The spelling of 131334101433132 in words is "one hundred thirty-one trillion, three hundred thirty-four billion, one hundred one million, four hundred thirty-three thousand, one hundred thirty-two".