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131335103153 is a prime number
BaseRepresentation
bin111101001010000101…
…1101010001010110001
3110112222222011111211202
41322110023222022301
54122433241300103
6140200131020545
712326414646242
oct1722413521261
9415888144752
10131335103153
1150776272971
1221553a3a755
13c5006804b7
1464dc926cc9
15363a189988
hex1e942ea2b1

131335103153 has 2 divisors, whose sum is σ = 131335103154. Its totient is φ = 131335103152.

The previous prime is 131335103149. The next prime is 131335103191. The reversal of 131335103153 is 351301533131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113654614129 + 17680489024 = 337127^2 + 132968^2 .

It is a cyclic number.

It is not a de Polignac number, because 131335103153 - 22 = 131335103149 is a prime.

It is not a weakly prime, because it can be changed into another prime (131335103113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65667551576 + 65667551577.

It is an arithmetic number, because the mean of its divisors is an integer number (65667551577).

Almost surely, 2131335103153 is an apocalyptic number.

It is an amenable number.

131335103153 is a deficient number, since it is larger than the sum of its proper divisors (1).

131335103153 is an equidigital number, since it uses as much as digits as its factorization.

131335103153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6075, while the sum is 29.

Adding to 131335103153 its reverse (351301533131), we get a palindrome (482636636284).

The spelling of 131335103153 in words is "one hundred thirty-one billion, three hundred thirty-five million, one hundred three thousand, one hundred fifty-three".