Base | Representation |
---|---|
bin | 10011000111001100111… |
… | …001000011110110001111 |
3 | 11122120010021120210022212 |
4 | 103013030321003312033 |
5 | 133004322022112221 |
6 | 2443211354301035 |
7 | 163614224230346 |
oct | 23071471036617 |
9 | 4576107523285 |
10 | 1313402535311 |
11 | 467013544359 |
12 | 192667a2777b |
13 | 96b129b76c9 |
14 | 477d7578b5d |
15 | 2427088bb5b |
hex | 131cce43d8f |
1313402535311 has 8 divisors (see below), whose sum is σ = 1370520536544. Its totient is φ = 1256285662720.
The previous prime is 1313402535307. The next prime is 1313402535349. The reversal of 1313402535311 is 1135352043131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1313402535311 - 22 = 1313402535307 is a prime.
It is a super-4 number, since 4×13134025353114 (a number of 50 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313402595311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2823071 + ... + 3255231.
It is an arithmetic number, because the mean of its divisors is an integer number (171315067068).
Almost surely, 21313402535311 is an apocalyptic number.
1313402535311 is a deficient number, since it is larger than the sum of its proper divisors (57118001233).
1313402535311 is a wasteful number, since it uses less digits than its factorization.
1313402535311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 564321.
The product of its (nonzero) digits is 16200, while the sum is 32.
Adding to 1313402535311 its reverse (1135352043131), we get a palindrome (2448754578442).
The spelling of 1313402535311 in words is "one trillion, three hundred thirteen billion, four hundred two million, five hundred thirty-five thousand, three hundred eleven".
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