Base | Representation |
---|---|
bin | 10011000111001100111… |
… | …101001101010000110011 |
3 | 11122120010100122000121022 |
4 | 103013030331031100303 |
5 | 133004322311404301 |
6 | 2443211433450055 |
7 | 163614236406014 |
oct | 23071475152063 |
9 | 4576110560538 |
10 | 1313403622451 |
11 | 467014117118 |
12 | 19266827092b |
13 | 96b12ca849b |
14 | 477d777d00b |
15 | 24270a03d1b |
hex | 131ccf4d433 |
1313403622451 has 2 divisors, whose sum is σ = 1313403622452. Its totient is φ = 1313403622450.
The previous prime is 1313403622441. The next prime is 1313403622469. The reversal of 1313403622451 is 1542263043131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1542263043131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313403622451 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313403622441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656701811225 + 656701811226.
It is an arithmetic number, because the mean of its divisors is an integer number (656701811226).
Almost surely, 21313403622451 is an apocalyptic number.
1313403622451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313403622451 is an equidigital number, since it uses as much as digits as its factorization.
1313403622451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 1313403622451 its reverse (1542263043131), we get a palindrome (2855666665582).
The spelling of 1313403622451 in words is "one trillion, three hundred thirteen billion, four hundred three million, six hundred twenty-two thousand, four hundred fifty-one".
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