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13134104531 is a prime number
BaseRepresentation
bin11000011101101101…
…01000011111010011
31020220100010122021222
430032312220133103
5203344312321111
610011141235255
7643322021642
oct141666503723
936810118258
1013134104531
11562a950149
122666702b2b
1313140c67b2
148c84b7359
1551d0e17db
hex30eda87d3

13134104531 has 2 divisors, whose sum is σ = 13134104532. Its totient is φ = 13134104530.

The previous prime is 13134104497. The next prime is 13134104561. The reversal of 13134104531 is 13540143131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13134104531 - 218 = 13133842387 is a prime.

It is a super-2 number, since 2×131341045312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13134104531.

It is not a weakly prime, because it can be changed into another prime (13134104561) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567052265 + 6567052266.

It is an arithmetic number, because the mean of its divisors is an integer number (6567052266).

Almost surely, 213134104531 is an apocalyptic number.

13134104531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134104531 is an equidigital number, since it uses as much as digits as its factorization.

13134104531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 13134104531 its reverse (13540143131), we get a palindrome (26674247662).

The spelling of 13134104531 in words is "thirteen billion, one hundred thirty-four million, one hundred four thousand, five hundred thirty-one".