Base | Representation |
---|---|
bin | 1011111100100000010110… |
… | …1011100101010000001001 |
3 | 1201111121102101021201120110 |
4 | 2333020011223211100021 |
5 | 3210142121424131100 |
6 | 43533420310344533 |
7 | 2523623242016331 |
oct | 277100553452011 |
9 | 51447371251513 |
10 | 13134105302025 |
11 | 4204163046014 |
12 | 158158935b149 |
13 | 743705230536 |
14 | 3359a08160c1 |
15 | 17b9acb21250 |
hex | bf205ae5409 |
13134105302025 has 12 divisors (see below), whose sum is σ = 21715054099472. Its totient is φ = 7004856161040.
The previous prime is 13134105302023. The next prime is 13134105302047. The reversal of 13134105302025 is 52020350143131.
It is not a de Polignac number, because 13134105302025 - 21 = 13134105302023 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13134105301983 and 13134105302001.
It is not an unprimeable number, because it can be changed into a prime (13134105302023) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 87560701939 + ... + 87560702088.
Almost surely, 213134105302025 is an apocalyptic number.
13134105302025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13134105302025 is a deficient number, since it is larger than the sum of its proper divisors (8580948797447).
13134105302025 is a wasteful number, since it uses less digits than its factorization.
13134105302025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 175121404040 (or 175121404035 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 13134105302025 its reverse (52020350143131), we get a palindrome (65154455445156).
The spelling of 13134105302025 in words is "thirteen trillion, one hundred thirty-four billion, one hundred five million, three hundred two thousand, twenty-five".
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