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1313413320203 is a prime number
BaseRepresentation
bin10011000111001101100…
…010001100111000001011
311122120011000212201102022
4103013031202030320023
5133004332302221303
62443212421355055
7163614415006235
oct23071542147013
94576130781368
101313413320203
11467019640196
1219266b568a8b
1396b14cc25ba
14477d8b85255
15242717bc438
hex131cd88ce0b

1313413320203 has 2 divisors, whose sum is σ = 1313413320204. Its totient is φ = 1313413320202.

The previous prime is 1313413320119. The next prime is 1313413320221. The reversal of 1313413320203 is 3020233143131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1313413320203 - 28 = 1313413319947 is a prime.

It is a super-2 number, since 2×13134133202032 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1313413320503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656706660101 + 656706660102.

It is an arithmetic number, because the mean of its divisors is an integer number (656706660102).

Almost surely, 21313413320203 is an apocalyptic number.

1313413320203 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313413320203 is an equidigital number, since it uses as much as digits as its factorization.

1313413320203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 1313413320203 its reverse (3020233143131), we get a palindrome (4333646463334).

The spelling of 1313413320203 in words is "one trillion, three hundred thirteen billion, four hundred thirteen million, three hundred twenty thousand, two hundred three".