Base | Representation |
---|---|
bin | 11101110111010001111101… |
… | …001111110010000101101010 |
3 | 122020001012011211100212121111 |
4 | 131313101331033302011222 |
5 | 114203402312001413002 |
6 | 1143201435123500534 |
7 | 36444106120524451 |
oct | 3567217517620552 |
9 | 566035154325544 |
10 | 131342201201002 |
11 | 38938a07548340 |
12 | 12892bb952774a |
13 | 583969379407c |
14 | 2460dd43c5b98 |
15 | 102b7a335d3d7 |
hex | 77747d3f216a |
131342201201002 has 32 divisors (see below), whose sum is σ = 216934555109184. Its totient is φ = 59142414393600.
The previous prime is 131342201200993. The next prime is 131342201201009. The reversal of 131342201201002 is 200102102243131.
It is a super-3 number, since 3×1313422012010023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (22).
It is not an unprimeable number, because it can be changed into a prime (131342201201009) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 272778738 + ... + 273259810.
It is an arithmetic number, because the mean of its divisors is an integer number (6779204847162).
Almost surely, 2131342201201002 is an apocalyptic number.
131342201201002 is a deficient number, since it is larger than the sum of its proper divisors (85592353908182).
131342201201002 is a wasteful number, since it uses less digits than its factorization.
131342201201002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 597174.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 131342201201002 its reverse (200102102243131), we get a palindrome (331444303444133).
The spelling of 131342201201002 in words is "one hundred thirty-one trillion, three hundred forty-two billion, two hundred one million, two hundred one thousand, two".
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