Base | Representation |
---|---|
bin | 1011111100100000110101… |
… | …0000011011010111111001 |
3 | 1201111121202020110001010202 |
4 | 2333020031100123113321 |
5 | 3210142401443321101 |
6 | 43533441050451545 |
7 | 2523626344236416 |
oct | 277101520332771 |
9 | 51447666401122 |
10 | 13134232401401 |
11 | 4204218866721 |
12 | 1581603a33bb5 |
13 | 743725671977 |
14 | 3359b365d10d |
15 | 17b9b8d7a36b |
hex | bf20d41b5f9 |
13134232401401 has 2 divisors, whose sum is σ = 13134232401402. Its totient is φ = 13134232401400.
The previous prime is 13134232401359. The next prime is 13134232401449. The reversal of 13134232401401 is 10410423243131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12773333040400 + 360899361001 = 3573980^2 + 600749^2 .
It is a cyclic number.
It is not a de Polignac number, because 13134232401401 - 234 = 13117052532217 is a prime.
It is not a weakly prime, because it can be changed into another prime (13134232401491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567116200700 + 6567116200701.
It is an arithmetic number, because the mean of its divisors is an integer number (6567116200701).
Almost surely, 213134232401401 is an apocalyptic number.
It is an amenable number.
13134232401401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134232401401 is an equidigital number, since it uses as much as digits as its factorization.
13134232401401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13134232401401 its reverse (10410423243131), we get a palindrome (23544655644532).
The spelling of 13134232401401 in words is "thirteen trillion, one hundred thirty-four billion, two hundred thirty-two million, four hundred one thousand, four hundred one".
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