Base | Representation |
---|---|
bin | 11101110111010010001011… |
… | …100010111100010001111011 |
3 | 122020001012210112210020100111 |
4 | 131313102023202330101323 |
5 | 114203403304410321012 |
6 | 1143201515013445151 |
7 | 36444115062625543 |
oct | 3567221342742173 |
9 | 566035715706314 |
10 | 131342441104507 |
11 | 3893901aa053a6 |
12 | 128930659407b7 |
13 | 58397013accc9 |
14 | 24610181d4323 |
15 | 102b7b944aba7 |
hex | 77748b8bc47b |
131342441104507 has 2 divisors, whose sum is σ = 131342441104508. Its totient is φ = 131342441104506.
The previous prime is 131342441104411. The next prime is 131342441104541. The reversal of 131342441104507 is 705401144243131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131342441104507 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131342441104507.
It is not a weakly prime, because it can be changed into another prime (131342441104597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671220552253 + 65671220552254.
It is an arithmetic number, because the mean of its divisors is an integer number (65671220552254).
Almost surely, 2131342441104507 is an apocalyptic number.
131342441104507 is a deficient number, since it is larger than the sum of its proper divisors (1).
131342441104507 is an equidigital number, since it uses as much as digits as its factorization.
131342441104507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 161280, while the sum is 40.
Adding to 131342441104507 its reverse (705401144243131), we get a palindrome (836743585347638).
The spelling of 131342441104507 in words is "one hundred thirty-one trillion, three hundred forty-two billion, four hundred forty-one million, one hundred four thousand, five hundred seven".
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