Base | Representation |
---|---|
bin | 111101001010010011… |
… | …1111000011001000001 |
3 | 110120000111002101101102 |
4 | 1322110213320121001 |
5 | 4122442140021231 |
6 | 140200553344145 |
7 | 12326534561504 |
oct | 1722447703101 |
9 | 416014071342 |
10 | 131342501441 |
11 | 5077a466358 |
12 | 21556408055 |
13 | c502070a98 |
14 | 64dd8d113b |
15 | 363ab4bacb |
hex | 1e949f8641 |
131342501441 has 2 divisors, whose sum is σ = 131342501442. Its totient is φ = 131342501440.
The previous prime is 131342501431. The next prime is 131342501461. The reversal of 131342501441 is 144105243131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114162894400 + 17179607041 = 337880^2 + 131071^2 .
It is a cyclic number.
It is not a de Polignac number, because 131342501441 - 26 = 131342501377 is a prime.
It is not a weakly prime, because it can be changed into another prime (131342501431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671250720 + 65671250721.
It is an arithmetic number, because the mean of its divisors is an integer number (65671250721).
Almost surely, 2131342501441 is an apocalyptic number.
It is an amenable number.
131342501441 is a deficient number, since it is larger than the sum of its proper divisors (1).
131342501441 is an equidigital number, since it uses as much as digits as its factorization.
131342501441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 131342501441 its reverse (144105243131), we get a palindrome (275447744572).
The spelling of 131342501441 in words is "one hundred thirty-one billion, three hundred forty-two million, five hundred one thousand, four hundred forty-one".
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