Base | Representation |
---|---|
bin | 11101110111010010111000… |
… | …111101011001011011000011 |
3 | 122020001021202122110021011011 |
4 | 131313102320331121123003 |
5 | 114203411334432424324 |
6 | 1143202122352101351 |
7 | 36444143004020161 |
oct | 3567227075313303 |
9 | 566037678407134 |
10 | 131343203014339 |
11 | 38939380a9a548 |
12 | 12893238b34857 |
13 | 58397c31b7724 |
14 | 246108b486231 |
15 | 102b81129bc94 |
hex | 7774b8f596c3 |
131343203014339 has 2 divisors, whose sum is σ = 131343203014340. Its totient is φ = 131343203014338.
The previous prime is 131343203014313. The next prime is 131343203014343. The reversal of 131343203014339 is 933410302343131.
It is a strong prime.
It is an emirp because it is prime and its reverse (933410302343131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131343203014339 - 229 = 131342666143427 is a prime.
It is not a weakly prime, because it can be changed into another prime (131343200014339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671601507169 + 65671601507170.
It is an arithmetic number, because the mean of its divisors is an integer number (65671601507170).
Almost surely, 2131343203014339 is an apocalyptic number.
131343203014339 is a deficient number, since it is larger than the sum of its proper divisors (1).
131343203014339 is an equidigital number, since it uses as much as digits as its factorization.
131343203014339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 40.
The spelling of 131343203014339 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred three million, fourteen thousand, three hundred thirty-nine".
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