Base | Representation |
---|---|
bin | 10011000111001110101… |
… | …001111001011101001111 |
3 | 11122120012100020121001202 |
4 | 103013032221321131033 |
5 | 133004402110140043 |
6 | 2443214332300115 |
7 | 163615033525520 |
oct | 23071651713517 |
9 | 4576170217052 |
10 | 1313432115023 |
11 | 467029207aa6 |
12 | 19267591163b |
13 | 96b18b732b2 |
14 | 477db478847 |
15 | 242732811b8 |
hex | 131cea7974f |
1313432115023 has 16 divisors (see below), whose sum is σ = 1556151367680. Its totient is φ = 1084650647136.
The previous prime is 1313432115019. The next prime is 1313432115031. The reversal of 1313432115023 is 3205112343131.
It is not a de Polignac number, because 1313432115023 - 22 = 1313432115019 is a prime.
It is a super-2 number, since 2×13134321150232 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313432115223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6832511 + ... + 7022112.
It is an arithmetic number, because the mean of its divisors is an integer number (97259460480).
Almost surely, 21313432115023 is an apocalyptic number.
1313432115023 is a deficient number, since it is larger than the sum of its proper divisors (242719252657).
1313432115023 is a wasteful number, since it uses less digits than its factorization.
1313432115023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13855126.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 1313432115023 its reverse (3205112343131), we get a palindrome (4518544458154).
The spelling of 1313432115023 in words is "one trillion, three hundred thirteen billion, four hundred thirty-two million, one hundred fifteen thousand, twenty-three".
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