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131343230413042 = 265671615206521
BaseRepresentation
bin11101110111010010111010…
…100101111010100011110010
3122020001021211120000021002221
4131313102322211322203302
5114203411413441204132
61143202125211231254
736444143455632604
oct3567227245724362
9566037746007087
10131343230413042
11389393955035aa
121289324614852a
1358397c8a8b68b
142461090d79174
15102b8138aee97
hex7774ba97a8f2

131343230413042 has 4 divisors (see below), whose sum is σ = 197014845619566. Its totient is φ = 65671615206520.

The previous prime is 131343230413039. The next prime is 131343230413079. The reversal of 131343230413042 is 240314032343131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 72418585227921 + 58924645185121 = 8509911^2 + 7676239^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131343230412989 and 131343230413007.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32835807603259 + ... + 32835807603262.

Almost surely, 2131343230413042 is an apocalyptic number.

131343230413042 is a deficient number, since it is larger than the sum of its proper divisors (65671615206524).

131343230413042 is an equidigital number, since it uses as much as digits as its factorization.

131343230413042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65671615206523.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 131343230413042 its reverse (240314032343131), we get a palindrome (371657262756173).

The spelling of 131343230413042 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred thirty million, four hundred thirteen thousand, forty-two".

Divisors: 1 2 65671615206521 131343230413042