Base | Representation |
---|---|
bin | 11101110111010010111010… |
… | …100101111010100011110010 |
3 | 122020001021211120000021002221 |
4 | 131313102322211322203302 |
5 | 114203411413441204132 |
6 | 1143202125211231254 |
7 | 36444143455632604 |
oct | 3567227245724362 |
9 | 566037746007087 |
10 | 131343230413042 |
11 | 389393955035aa |
12 | 1289324614852a |
13 | 58397c8a8b68b |
14 | 2461090d79174 |
15 | 102b8138aee97 |
hex | 7774ba97a8f2 |
131343230413042 has 4 divisors (see below), whose sum is σ = 197014845619566. Its totient is φ = 65671615206520.
The previous prime is 131343230413039. The next prime is 131343230413079. The reversal of 131343230413042 is 240314032343131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 72418585227921 + 58924645185121 = 8509911^2 + 7676239^2 .
It is a junction number, because it is equal to n+sod(n) for n = 131343230412989 and 131343230413007.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32835807603259 + ... + 32835807603262.
Almost surely, 2131343230413042 is an apocalyptic number.
131343230413042 is a deficient number, since it is larger than the sum of its proper divisors (65671615206524).
131343230413042 is an equidigital number, since it uses as much as digits as its factorization.
131343230413042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65671615206523.
The product of its (nonzero) digits is 62208, while the sum is 34.
Adding to 131343230413042 its reverse (240314032343131), we get a palindrome (371657262756173).
The spelling of 131343230413042 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred thirty million, four hundred thirteen thousand, forty-two".
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