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131343232034281 is a prime number
BaseRepresentation
bin11101110111010010111010…
…101100000110010111101001
3122020001021211200001122000211
4131313102322230012113221
5114203411414400044111
61143202125310101121
736444143505464341
oct3567227254062751
9566037750048024
10131343232034281
1138939396410673
12128932467aa7a1
1358397c92085a7
14246109127bd21
15102b813ad0521
hex7774bab065e9

131343232034281 has 2 divisors, whose sum is σ = 131343232034282. Its totient is φ = 131343232034280.

The previous prime is 131343232034173. The next prime is 131343232034309. The reversal of 131343232034281 is 182430232343131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96382501216681 + 34960730817600 = 9817459^2 + 5912760^2 .

It is a cyclic number.

It is not a de Polignac number, because 131343232034281 - 213 = 131343232026089 is a prime.

It is a super-2 number, since 2×1313432320342812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131343232134281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65671616017140 + 65671616017141.

It is an arithmetic number, because the mean of its divisors is an integer number (65671616017141).

Almost surely, 2131343232034281 is an apocalyptic number.

It is an amenable number.

131343232034281 is a deficient number, since it is larger than the sum of its proper divisors (1).

131343232034281 is an equidigital number, since it uses as much as digits as its factorization.

131343232034281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 131343232034281 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred thirty-two million, thirty-four thousand, two hundred eighty-one".