Base | Representation |
---|---|
bin | 11101110111010010111010… |
… | …101101100100101000110010 |
3 | 122020001021211200210020200121 |
4 | 131313102322231210220302 |
5 | 114203411414444423102 |
6 | 1143202125322240454 |
7 | 36444143511663142 |
oct | 3567227255445062 |
9 | 566037750706617 |
10 | 131343232420402 |
11 | 38939396654782 |
12 | 1289324695612a |
13 | 58397c9312272 |
14 | 246109133c922 |
15 | 102b813b59b37 |
hex | 7774bab64a32 |
131343232420402 has 4 divisors (see below), whose sum is σ = 197014848630606. Its totient is φ = 65671616210200.
The previous prime is 131343232420297. The next prime is 131343232420447. The reversal of 131343232420402 is 204024232343131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 110075999707521 + 21267232712881 = 10491711^2 + 4611641^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32835808105099 + ... + 32835808105102.
Almost surely, 2131343232420402 is an apocalyptic number.
131343232420402 is a deficient number, since it is larger than the sum of its proper divisors (65671616210204).
131343232420402 is an equidigital number, since it uses as much as digits as its factorization.
131343232420402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65671616210203.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 131343232420402 its reverse (204024232343131), we get a palindrome (335367464763533).
The spelling of 131343232420402 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred thirty-two million, four hundred twenty thousand, four hundred two".
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