Base | Representation |
---|---|
bin | 10011000111001110111… |
… | …010110000100100000011 |
3 | 11122120012122120011012012 |
4 | 103013032322300210003 |
5 | 133004404223110133 |
6 | 2443215011123135 |
7 | 163615116225053 |
oct | 23071672604403 |
9 | 4576178504165 |
10 | 1313436535043 |
11 | 467030756906 |
12 | 1926772a34ab |
13 | 96b19a600a9 |
14 | 477dbca9563 |
15 | 24273855b48 |
hex | 131ceeb0903 |
1313436535043 has 2 divisors, whose sum is σ = 1313436535044. Its totient is φ = 1313436535042.
The previous prime is 1313436535027. The next prime is 1313436535051. The reversal of 1313436535043 is 3405356343131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3405356343131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313436535043 - 24 = 1313436535027 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313436535013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656718267521 + 656718267522.
It is an arithmetic number, because the mean of its divisors is an integer number (656718267522).
Almost surely, 21313436535043 is an apocalyptic number.
1313436535043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313436535043 is an equidigital number, since it uses as much as digits as its factorization.
1313436535043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 583200, while the sum is 41.
The spelling of 1313436535043 in words is "one trillion, three hundred thirteen billion, four hundred thirty-six million, five hundred thirty-five thousand, forty-three".
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