Base | Representation |
---|---|
bin | 11101110111010100000110… |
… | …111000110101101111001000 |
3 | 122020001102010202121111100011 |
4 | 131313110012320311233020 |
5 | 114203422024133124230 |
6 | 1143202500214521304 |
7 | 36444220260666001 |
oct | 3567240670655710 |
9 | 566042122544304 |
10 | 131344510442440 |
11 | 38939992000639 |
12 | 12893542966234 |
13 | 5839971023719 |
14 | 2461172d7c1a8 |
15 | 102b88ae57e2a |
hex | 777506e35bc8 |
131344510442440 has 16 divisors (see below), whose sum is σ = 295525148495580. Its totient is φ = 52537804176960.
The previous prime is 131344510442437. The next prime is 131344510442443. The reversal of 131344510442440 is 44244015443131.
It is an interprime number because it is at equal distance from previous prime (131344510442437) and next prime (131344510442443).
It can be written as a sum of positive squares in 2 ways, for example, as 127897687982596 + 3446822459844 = 11309186^2 + 1856562^2 .
It is a Harshad number since it is a multiple of its sum of digits (40), and also a Moran number because the ratio is a prime number: 3283612761061 = 131344510442440 / (1 + 3 + 1 + 3 + 4 + 4 + 5 + 1 + 0 + 4 + 4 + 2 + 4 + 4 + 0).
It is a junction number, because it is equal to n+sod(n) for n = 131344510442393 and 131344510442402.
It is not an unprimeable number, because it can be changed into a prime (131344510442443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1641806380491 + ... + 1641806380570.
Almost surely, 2131344510442440 is an apocalyptic number.
131344510442440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131344510442440 is an abundant number, since it is smaller than the sum of its proper divisors (164180638053140).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131344510442440 is a wasteful number, since it uses less digits than its factorization.
131344510442440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3283612761072 (or 3283612761068 counting only the distinct ones).
The product of its (nonzero) digits is 368640, while the sum is 40.
Adding to 131344510442440 its reverse (44244015443131), we get a palindrome (175588525885571).
The spelling of 131344510442440 in words is "one hundred thirty-one trillion, three hundred forty-four billion, five hundred ten million, four hundred forty-two thousand, four hundred forty".
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