Base | Representation |
---|---|
bin | 10011000111010100001… |
… | …010110000100010101110 |
3 | 11122120102210022002122111 |
4 | 103013110022300202232 |
5 | 133010044300142332 |
6 | 2443231435034234 |
7 | 163620236003662 |
oct | 23072412604256 |
9 | 4576383262574 |
10 | 1313524615342 |
11 | 467076446945 |
12 | 1926a089b97a |
13 | 96b3208c304 |
14 | 478098768a2 |
15 | 2427b453947 |
hex | 131d42b08ae |
1313524615342 has 8 divisors (see below), whose sum is σ = 1970307209232. Its totient is φ = 656755545600.
The previous prime is 1313524615339. The next prime is 1313524615369. The reversal of 1313524615342 is 2435164253131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1313524615295 and 1313524615304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3134634 + ... + 3528877.
It is an arithmetic number, because the mean of its divisors is an integer number (246288401154).
Almost surely, 21313524615342 is an apocalyptic number.
1313524615342 is a deficient number, since it is larger than the sum of its proper divisors (656782593890).
1313524615342 is an equidigital number, since it uses as much as digits as its factorization.
1313524615342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6762074.
The product of its digits is 259200, while the sum is 40.
Adding to 1313524615342 its reverse (2435164253131), we get a palindrome (3748688868473).
The spelling of 1313524615342 in words is "one trillion, three hundred thirteen billion, five hundred twenty-four million, six hundred fifteen thousand, three hundred forty-two".
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