Base | Representation |
---|---|
bin | 1011111100101101111011… |
… | …1011101111110111100011 |
3 | 1201111221211101210111200212 |
4 | 2333023132323233313203 |
5 | 3210222103022230213 |
6 | 43535222113204335 |
7 | 2524112461060421 |
oct | 277133673576743 |
9 | 51457741714625 |
10 | 13137750195683 |
11 | 4205763537623 |
12 | 1582225b606ab |
13 | 743b663cb749 |
14 | 335c28930111 |
15 | 17bb22aee9a8 |
hex | bf2deeefde3 |
13137750195683 has 2 divisors, whose sum is σ = 13137750195684. Its totient is φ = 13137750195682.
The previous prime is 13137750195673. The next prime is 13137750195763. The reversal of 13137750195683 is 38659105773131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13137750195683 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13137750195673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6568875097841 + 6568875097842.
It is an arithmetic number, because the mean of its divisors is an integer number (6568875097842).
Almost surely, 213137750195683 is an apocalyptic number.
13137750195683 is a deficient number, since it is larger than the sum of its proper divisors (1).
13137750195683 is an equidigital number, since it uses as much as digits as its factorization.
13137750195683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14288400, while the sum is 59.
The spelling of 13137750195683 in words is "thirteen trillion, one hundred thirty-seven billion, seven hundred fifty million, one hundred ninety-five thousand, six hundred eighty-three".
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