131400111043 has 2 divisors, whose sum is σ = 131400111044. Its totient is φ = 131400111042.

The previous prime is 131400111013. The next prime is 131400111097. The reversal of 131400111043 is 340111004131.

It is a weak prime.

It is an emirp because it is prime and its reverse (340111004131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131400111043 - 2²¹ = 131398013891 is a prime.

It is a super-2 number, since 2×131400111043² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131400111043.

It is not a weakly prime, because it can be changed into another prime (131400111013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700055521 + 65700055522.

It is an arithmetic number, because the mean of its divisors is an integer number (65700055522).

Almost surely, 2^131400111043 is an apocalyptic number.

131400111043 is a deficient number, since it is larger than the sum of its proper divisors (1).

131400111043 is an equidigital number, since it uses as much as digits as its factorization.

131400111043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 131400111043 its reverse (340111004131), we get a palindrome (471511115174).

The spelling of 131400111043 in words is "one hundred thirty-one billion, four hundred million, one hundred eleven thousand, forty-three".