131400314243341 has 8 divisors (see below), whose sum is σ = 154372397153184. Its totient is φ = 110265997966320.

The previous prime is 131400314243327. The next prime is 131400314243351. The reversal of 131400314243341 is 143342413004131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131400314243341 - 2⁷ = 131400314243213 is a prime.

It is a super-3 number, since 3×131400314243341³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131400314243297 and 131400314243306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131400314243351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 459441658051 + ... + 459441658336.

It is an arithmetic number, because the mean of its divisors is an integer number (19296549644148).

Almost surely, 2^{131400314243341} is an apocalyptic number.

131400314243341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131400314243341 is a deficient number, since it is larger than the sum of its proper divisors (22972082909843).

131400314243341 is a wasteful number, since it uses less digits than its factorization.

131400314243341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 918883316411.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 131400314243341 its reverse (143342413004131), we get a palindrome (274742727247472).

The spelling of 131400314243341 in words is "one hundred thirty-one trillion, four hundred billion, three hundred fourteen million, two hundred forty-three thousand, three hundred forty-one".