Base | Representation |
---|---|
bin | 11000011110011010… |
… | …01111111001100001 |
3 | 1020220202021211210101 |
4 | 30033031033321201 |
5 | 203402322024441 |
6 | 10011512302401 |
7 | 643423303315 |
oct | 141715177141 |
9 | 36822254711 |
10 | 13140033121 |
11 | 563322a406 |
12 | 26686a1a01 |
13 | 13153c1137 |
14 | 8c91bbb45 |
15 | 51d8b3231 |
hex | 30f34fe61 |
13140033121 has 2 divisors, whose sum is σ = 13140033122. Its totient is φ = 13140033120.
The previous prime is 13140033047. The next prime is 13140033143. The reversal of 13140033121 is 12133004131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8075718225 + 5064314896 = 89865^2 + 71164^2 .
It is a cyclic number.
It is not a de Polignac number, because 13140033121 - 217 = 13139902049 is a prime.
It is not a weakly prime, because it can be changed into another prime (13140033161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570016560 + 6570016561.
It is an arithmetic number, because the mean of its divisors is an integer number (6570016561).
Almost surely, 213140033121 is an apocalyptic number.
It is an amenable number.
13140033121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13140033121 is an equidigital number, since it uses as much as digits as its factorization.
13140033121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13140033121 its reverse (12133004131), we get a palindrome (25273037252).
The spelling of 13140033121 in words is "thirteen billion, one hundred forty million, thirty-three thousand, one hundred twenty-one".
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