13140102101000 has 768 divisors, whose sum is σ = 38743795584000. Its totient is φ = 4146308812800.

The previous prime is 13140102100999. The next prime is 13140102101003. The reversal of 13140102101000 is 10120104131.

13140102101000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×13140102101000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is not an unprimeable number, because it can be changed into a prime (13140102101003) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 13367346509 + ... + 13367347491.

It is an arithmetic number, because the mean of its divisors is an integer number (50447650500).

Almost surely, 2^{13140102101000} is an apocalyptic number.

13140102101000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13140102101000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19371897792000).

13140102101000 is an abundant number, since it is smaller than the sum of its proper divisors (25603693483000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13140102101000 is a wasteful number, since it uses less digits than its factorization.

13140102101000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1479 (or 1458 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 13140102101000 its reverse (10120104131), we get a palindrome (13150222205131).

The spelling of 13140102101000 in words is "thirteen trillion, one hundred forty billion, one hundred two million, one hundred one thousand".