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131401051 is a prime number
BaseRepresentation
bin1111101010100…
…00010101011011
3100011020212100121
413311100111123
5232114313201
621012214111
73153614305
oct765202533
9304225317
10131401051
1168199611
123800a337
13212b9402
1413646975
15b8089a1
hex7d5055b

131401051 has 2 divisors, whose sum is σ = 131401052. Its totient is φ = 131401050.

The previous prime is 131401037. The next prime is 131401057. The reversal of 131401051 is 150104131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131401051 - 25 = 131401019 is a prime.

It is not a weakly prime, because it can be changed into another prime (131401057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700525 + 65700526.

It is an arithmetic number, because the mean of its divisors is an integer number (65700526).

Almost surely, 2131401051 is an apocalyptic number.

131401051 is a deficient number, since it is larger than the sum of its proper divisors (1).

131401051 is an equidigital number, since it uses as much as digits as its factorization.

131401051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 131401051 is about 11463.0297478459. The cubic root of 131401051 is about 508.3930594578.

Adding to 131401051 its reverse (150104131), we get a palindrome (281505182).

It can be divided in two parts, 13140 and 1051, that multiplied together give a triangular number (13810140 = T5255).

The spelling of 131401051 in words is "one hundred thirty-one million, four hundred one thousand, fifty-one".