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131401140983617 is a prime number
BaseRepresentation
bin11101111000001000110110…
…010101001101011101000001
3122020020211022102222001112011
4131320020312111031131001
5114210334014042433432
61143244503435532521
736451263524440411
oct3570106625153501
9566224272861464
10131401140983617
1138960a0251238a
12128a25082ba141
1358420c768c19b
142463bc6134641
15102d0a2987847
hex77823654d741

131401140983617 has 2 divisors, whose sum is σ = 131401140983618. Its totient is φ = 131401140983616.

The previous prime is 131401140983573. The next prime is 131401140983621. The reversal of 131401140983617 is 716389041104131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110492872610481 + 20908268373136 = 10511559^2 + 4572556^2 .

It is an emirp because it is prime and its reverse (716389041104131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131401140983617 is a prime.

It is not a weakly prime, because it can be changed into another prime (131401140983687) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700570491808 + 65700570491809.

It is an arithmetic number, because the mean of its divisors is an integer number (65700570491809).

Almost surely, 2131401140983617 is an apocalyptic number.

It is an amenable number.

131401140983617 is a deficient number, since it is larger than the sum of its proper divisors (1).

131401140983617 is an equidigital number, since it uses as much as digits as its factorization.

131401140983617 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 435456, while the sum is 49.

The spelling of 131401140983617 in words is "one hundred thirty-one trillion, four hundred one billion, one hundred forty million, nine hundred eighty-three thousand, six hundred seventeen".