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13140120134023 = 31423874843033
BaseRepresentation
bin1011111100110110110000…
…1100010110000110000111
31201112011221120020211220221
42333031230030112012013
53210241431223242043
643540253213205211
72524225266160561
oct277155414260607
951464846224827
1013140120134023
11420676a287353
121582787790807
137441533c031c
14335db15a6331
1517bc10bd88ed
hexbf36c316187

13140120134023 has 4 divisors (see below), whose sum is σ = 13563994977088. Its totient is φ = 12716245290960.

The previous prime is 13140120134017. The next prime is 13140120134033. The reversal of 13140120134023 is 32043102104131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13140120134023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140120134033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211937421486 + ... + 211937421547.

It is an arithmetic number, because the mean of its divisors is an integer number (3390998744272).

Almost surely, 213140120134023 is an apocalyptic number.

13140120134023 is a deficient number, since it is larger than the sum of its proper divisors (423874843065).

13140120134023 is an equidigital number, since it uses as much as digits as its factorization.

13140120134023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 423874843064.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13140120134023 its reverse (32043102104131), we get a palindrome (45183222238154).

The spelling of 13140120134023 in words is "thirteen trillion, one hundred forty billion, one hundred twenty million, one hundred thirty-four thousand, twenty-three".

Divisors: 1 31 423874843033 13140120134023