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131401312423 = 163806143021
BaseRepresentation
bin111101001100000100…
…0001110100010100111
3110120011120202021212221
41322120020032202213
54123102213444143
6140210454053211
712331150504213
oct1723010164247
9416146667787
10131401312423
11507aa684977
122157204a207
13c5112c2794
14650763d943
153640db72ed
hex1e9820e8a7

131401312423 has 4 divisors (see below), whose sum is σ = 132207455608. Its totient is φ = 130595169240.

The previous prime is 131401312411. The next prime is 131401312577. The reversal of 131401312423 is 324213104131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131401312423 - 213 = 131401304231 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131401612423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 403071348 + ... + 403071673.

It is an arithmetic number, because the mean of its divisors is an integer number (33051863902).

Almost surely, 2131401312423 is an apocalyptic number.

131401312423 is a deficient number, since it is larger than the sum of its proper divisors (806143185).

131401312423 is an equidigital number, since it uses as much as digits as its factorization.

131401312423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 806143184.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131401312423 its reverse (324213104131), we get a palindrome (455614416554).

The spelling of 131401312423 in words is "one hundred thirty-one billion, four hundred one million, three hundred twelve thousand, four hundred twenty-three".

Divisors: 1 163 806143021 131401312423