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131401413140411 is a prime number
BaseRepresentation
bin11101111000001001000110…
…100011011001111110111011
3122020020212000102002001110102
4131320021012203121332323
5114210340043230443121
61143244550441110015
736451303340643431
oct3570110643317673
9566225012061412
10131401413140411
11389610320a9857
12128a258348830b
13584213bb8b8cb
142463c1033ad51
15102d0bb7e690b
hex7782468d9fbb

131401413140411 has 2 divisors, whose sum is σ = 131401413140412. Its totient is φ = 131401413140410.

The previous prime is 131401413140369. The next prime is 131401413140419. The reversal of 131401413140411 is 114041314104131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131401413140411 - 222 = 131401408946107 is a prime.

It is not a weakly prime, because it can be changed into another prime (131401413140419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65700706570205 + 65700706570206.

It is an arithmetic number, because the mean of its divisors is an integer number (65700706570206).

Almost surely, 2131401413140411 is an apocalyptic number.

131401413140411 is a deficient number, since it is larger than the sum of its proper divisors (1).

131401413140411 is an equidigital number, since it uses as much as digits as its factorization.

131401413140411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 131401413140411 its reverse (114041314104131), we get a palindrome (245442727244542).

The spelling of 131401413140411 in words is "one hundred thirty-one trillion, four hundred one billion, four hundred thirteen million, one hundred forty thousand, four hundred eleven".