Base | Representation |
---|---|
bin | 10011000111110001010… |
… | …110011101101100011100 |
3 | 11122121200220120202021100 |
4 | 103013301112131230130 |
5 | 133012100120120012 |
6 | 2443352205033100 |
7 | 163635332415642 |
oct | 23076126355434 |
9 | 4577626522240 |
10 | 1314014223132 |
11 | 4672a7855486 |
12 | 1927b8855790 |
13 | 96bac646170 |
14 | 478548c5192 |
15 | 242a94178dc |
hex | 131f159db1c |
1314014223132 has 72 divisors (see below), whose sum is σ = 3579263913680. Its totient is φ = 404060555520.
The previous prime is 1314014223121. The next prime is 1314014223133. The reversal of 1314014223132 is 2313224104131.
1314014223132 is a `hidden beast` number, since 1 + 3 + 1 + 401 + 4 + 223 + 1 + 32 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 1314014223096 and 1314014223105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1314014223133) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 119494 + ... + 1625517.
Almost surely, 21314014223132 is an apocalyptic number.
1314014223132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1314014223132 is an abundant number, since it is smaller than the sum of its proper divisors (2265249690548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1314014223132 is a wasteful number, since it uses less digits than its factorization.
1314014223132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1746643 (or 1746638 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1314014223132 its reverse (2313224104131), we get a palindrome (3627238327263).
The spelling of 1314014223132 in words is "one trillion, three hundred fourteen billion, fourteen million, two hundred twenty-three thousand, one hundred thirty-two".
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