131402031241032 has 80 divisors (see below), whose sum is σ = 372481661669040. Its totient is φ = 43272958061664.

The previous prime is 131402031241031. The next prime is 131402031241043. The reversal of 131402031241032 is 230142130204131.

131402031241032 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 0 + 203 + 12 + 410 + 32 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 131402031240987 and 131402031241005.

It is not an unprimeable number, because it can be changed into a prime (131402031241031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 1221517978 + ... + 1221625545.

It is an arithmetic number, because the mean of its divisors is an integer number (4656020770863).

Almost surely, 2^{131402031241032} is an apocalyptic number.

131402031241032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131402031241032 is an abundant number, since it is smaller than the sum of its proper divisors (241079630428008).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131402031241032 is a wasteful number, since it uses less digits than its factorization.

131402031241032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2443143624 (or 2443143611 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 131402031241032 its reverse (230142130204131), we get a palindrome (361544161445163).

The spelling of 131402031241032 in words is "one hundred thirty-one trillion, four hundred two billion, thirty-one million, two hundred forty-one thousand, thirty-two".