Base | Representation |
---|---|
bin | 11101111000001001110111… |
… | …011011110011101101001001 |
3 | 122020020221010120020000220102 |
4 | 131320021313123303231021 |
5 | 114210343233201412301 |
6 | 1143245204054335145 |
7 | 36451332556420541 |
oct | 3570116733635511 |
9 | 566227116200812 |
10 | 131402233232201 |
11 | 38961413012968 |
12 | 128a277205a4b5 |
13 | 584223ca57919 |
14 | 2463c8b216321 |
15 | 102d1187dbb6b |
hex | 7782776f3b49 |
131402233232201 has 2 divisors, whose sum is σ = 131402233232202. Its totient is φ = 131402233232200.
The previous prime is 131402233232173. The next prime is 131402233232213. The reversal of 131402233232201 is 102232332204131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 82918307190601 + 48483926041600 = 9105949^2 + 6963040^2 .
It is a cyclic number.
It is not a de Polignac number, because 131402233232201 - 214 = 131402233215817 is a prime.
It is not a weakly prime, because it can be changed into another prime (131402233252201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701116616100 + 65701116616101.
It is an arithmetic number, because the mean of its divisors is an integer number (65701116616101).
Almost surely, 2131402233232201 is an apocalyptic number.
It is an amenable number.
131402233232201 is a deficient number, since it is larger than the sum of its proper divisors (1).
131402233232201 is an equidigital number, since it uses as much as digits as its factorization.
131402233232201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 131402233232201 its reverse (102232332204131), we get a palindrome (233634565436332).
The spelling of 131402233232201 in words is "one hundred thirty-one trillion, four hundred two billion, two hundred thirty-three million, two hundred thirty-two thousand, two hundred one".
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