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13140223405 = 52628044681
BaseRepresentation
bin11000011110011011…
…11110010110101101
31020220202122111210221
430033031332112231
5203402344122110
610011520331341
7643425025141
oct141715762655
936822574727
1013140223405
11563334a371
122668773b51
13131545992a
148c922b221
1551d8ee7da
hex30f37e5ad

13140223405 has 4 divisors (see below), whose sum is σ = 15768268092. Its totient is φ = 10512178720.

The previous prime is 13140223391. The next prime is 13140223451. The reversal of 13140223405 is 50432204131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7819688041 + 5320535364 = 88429^2 + 72942^2 .

It is not a de Polignac number, because 13140223405 - 213 = 13140215213 is a prime.

It is a super-2 number, since 2×131402234052 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13140223405.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314022336 + ... + 1314022345.

It is an arithmetic number, because the mean of its divisors is an integer number (3942067023).

Almost surely, 213140223405 is an apocalyptic number.

It is an amenable number.

13140223405 is a deficient number, since it is larger than the sum of its proper divisors (2628044687).

13140223405 is an equidigital number, since it uses as much as digits as its factorization.

13140223405 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2628044686.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13140223405 its reverse (50432204131), we get a palindrome (63572427536).

The spelling of 13140223405 in words is "thirteen billion, one hundred forty million, two hundred twenty-three thousand, four hundred five".

Divisors: 1 5 2628044681 13140223405