Base | Representation |
---|---|
bin | 11101111000001001111011… |
… | …101001110110001110011011 |
3 | 122020020221022111102111102201 |
4 | 131320021323221312032123 |
5 | 114210343404312141103 |
6 | 1143245215103511031 |
7 | 36451334406212212 |
oct | 3570117351661633 |
9 | 566227274374381 |
10 | 131402304021403 |
11 | 38961449a72938 |
12 | 128a27918b8477 |
13 | 584225161171c |
14 | 2463c967a2079 |
15 | 102d11eb2151d |
hex | 77827ba7639b |
131402304021403 has 32 divisors (see below), whose sum is σ = 134212437216000. Its totient is φ = 128627257651200.
The previous prime is 131402304021379. The next prime is 131402304021431. The reversal of 131402304021403 is 304120403204131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 131402304021403 - 221 = 131402301924251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131402304021503) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11311202251 + ... + 11311213867.
It is an arithmetic number, because the mean of its divisors is an integer number (4194138663000).
Almost surely, 2131402304021403 is an apocalyptic number.
131402304021403 is a deficient number, since it is larger than the sum of its proper divisors (2810133194597).
131402304021403 is a wasteful number, since it uses less digits than its factorization.
131402304021403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13975.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 131402304021403 its reverse (304120403204131), we get a palindrome (435522707225534).
The spelling of 131402304021403 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred four million, twenty-one thousand, four hundred three".
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