Base | Representation |
---|---|
bin | 11101111000001001111101… |
… | …111000011111000110111011 |
3 | 122020020221102002210012111001 |
4 | 131320021331320133012323 |
5 | 114210343443400211212 |
6 | 1143245222521145431 |
7 | 36451335342065416 |
oct | 3570117570370673 |
9 | 566227362705431 |
10 | 131402341413307 |
11 | 38961469091a38 |
12 | 128a27a232b277 |
13 | 58422592a4103 |
14 | 2463c9b736b7d |
15 | 102d12305a657 |
hex | 77827de1f1bb |
131402341413307 has 2 divisors, whose sum is σ = 131402341413308. Its totient is φ = 131402341413306.
The previous prime is 131402341413281. The next prime is 131402341413383. The reversal of 131402341413307 is 703314143204131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131402341413307 - 215 = 131402341380539 is a prime.
It is not a weakly prime, because it can be changed into another prime (131402341413407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701170706653 + 65701170706654.
It is an arithmetic number, because the mean of its divisors is an integer number (65701170706654).
Almost surely, 2131402341413307 is an apocalyptic number.
131402341413307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131402341413307 is an equidigital number, since it uses as much as digits as its factorization.
131402341413307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 37.
Adding to 131402341413307 its reverse (703314143204131), we get a palindrome (834716484617438).
The spelling of 131402341413307 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred forty-one million, four hundred thirteen thousand, three hundred seven".
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