Base | Representation |
---|---|
bin | 1011111100110111001101… |
… | …0111100011110111100111 |
3 | 1201112012020221202210221102 |
4 | 2333031303113203313213 |
5 | 3210242203032431120 |
6 | 43540313153310315 |
7 | 2524231260325301 |
oct | 277156327436747 |
9 | 51465227683842 |
10 | 13140240514535 |
11 | 4206821228a82 |
12 | 15827bbb6539b |
13 | 74417231b4b4 |
14 | 335dc3580971 |
15 | 17bc1b566d75 |
hex | bf3735e3de7 |
13140240514535 has 4 divisors (see below), whose sum is σ = 15768288617448. Its totient is φ = 10512192411624.
The previous prime is 13140240514507. The next prime is 13140240514537. The reversal of 13140240514535 is 53541504204131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13140240514535 - 222 = 13140236320231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13140240514537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314024051449 + ... + 1314024051458.
It is an arithmetic number, because the mean of its divisors is an integer number (3942072154362).
Almost surely, 213140240514535 is an apocalyptic number.
13140240514535 is a deficient number, since it is larger than the sum of its proper divisors (2628048102913).
13140240514535 is an equidigital number, since it uses as much as digits as its factorization.
13140240514535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2628048102912.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 13140240514535 its reverse (53541504204131), we get a palindrome (66681744718666).
The spelling of 13140240514535 in words is "thirteen trillion, one hundred forty billion, two hundred forty million, five hundred fourteen thousand, five hundred thirty-five".
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